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Who wants my 20 points? Plz answer this question no spam I will report!!!!!!I NEED FULL EXPLANATION!!!

for a cubic polynomia

Question

Who wants my 20 points? Plz answer this question no spam I will report!!!!!!I NEED FULL EXPLANATION!!!

for a cubic polynomial p(x) is ax³+bx²+cx+d which of the statements is correct:

a) sum of zeroes is -b/a

b) product of zeroes is -d/a

c) sum of products taken two at a time is c/a

d) sum of zeroes is +b/a

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Mathematics
3 months
2021-07-24T13:56:07+00:00
2021-07-24T13:56:07+00:00 2 Answers
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## Answers ( )

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Answer:Answer:As one of the zeros of polynomial is 0, then (x-0) =x is a factor of given polynomial.Answer:As one of the zeros of polynomial is 0, then (x-0) =x is a factor of given polynomial.Since x is a factor , d= 0Answer:As one of the zeros of polynomial is 0, then (x-0) =x is a factor of given polynomial.Since x is a factor , d= 0ax^3+bx^2+cx+d = ax^3+bx^2+cxAnswer:As one of the zeros of polynomial is 0, then (x-0) =x is a factor of given polynomial.Since x is a factor , d= 0ax^3+bx^2+cx+d = ax^3+bx^2+cx= x(ax^2+bx+c)Answer:As one of the zeros of polynomial is 0, then (x-0) =x is a factor of given polynomial.Since x is a factor , d= 0ax^3+bx^2+cx+d = ax^3+bx^2+cx= x(ax^2+bx+c)Other two roots are roots ofAnswer:As one of the zeros of polynomial is 0, then (x-0) =x is a factor of given polynomial.Since x is a factor , d= 0ax^3+bx^2+cx+d = ax^3+bx^2+cx= x(ax^2+bx+c)Other two roots are roots ofax^2+bx+c = 0Answer:As one of the zeros of polynomial is 0, then (x-0) =x is a factor of given polynomial.Since x is a factor , d= 0ax^3+bx^2+cx+d = ax^3+bx^2+cx= x(ax^2+bx+c)Other two roots are roots ofax^2+bx+c = 0For a quadratic equation ax^2+bx+c = 0Answer:As one of the zeros of polynomial is 0, then (x-0) =x is a factor of given polynomial.Since x is a factor , d= 0ax^3+bx^2+cx+d = ax^3+bx^2+cx= x(ax^2+bx+c)Other two roots are roots ofax^2+bx+c = 0For a quadratic equation ax^2+bx+c = 0Product of roots = c/aAnswer:As one of the zeros of polynomial is 0, then (x-0) =x is a factor of given polynomial.Since x is a factor , d= 0ax^3+bx^2+cx+d = ax^3+bx^2+cx= x(ax^2+bx+c)Other two roots are roots ofax^2+bx+c = 0For a quadratic equation ax^2+bx+c = 0Product of roots = c/aSum of roots = -b/aAnswer:As one of the zeros of polynomial is 0, then (x-0) =x is a factor of given polynomial.Since x is a factor , d= 0ax^3+bx^2+cx+d = ax^3+bx^2+cx= x(ax^2+bx+c)Other two roots are roots ofax^2+bx+c = 0For a quadratic equation ax^2+bx+c = 0Product of roots = c/aSum of roots = -b/aSoAnswer:As one of the zeros of polynomial is 0, then (x-0) =x is a factor of given polynomial.Since x is a factor , d= 0ax^3+bx^2+cx+d = ax^3+bx^2+cx= x(ax^2+bx+c)Other two roots are roots ofax^2+bx+c = 0For a quadratic equation ax^2+bx+c = 0Product of roots = c/aSum of roots = -b/aSoProduct of other two roots = c/aAnswer:As one of the zeros of polynomial is 0, then (x-0) =x is a factor of given polynomial.Since x is a factor , d= 0ax^3+bx^2+cx+d = ax^3+bx^2+cx= x(ax^2+bx+c)Other two roots are roots ofax^2+bx+c = 0For a quadratic equation ax^2+bx+c = 0Product of roots = c/aSum of roots = -b/aSoProduct of other two roots = c/a