Code Blocks doesn't show any error but still can't show output (0xC00000FD)

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I have this code:

#include <iostream>
#include <iomanip>

using namespace std;
main()
{
    int i, n, a[n], b[n], c[n];

    cout << "Program kreira nizove po matematickoj zavisnosti" << endl;
    cout << "Unesite vrednost n =" << endl;
    cin >> n;

    for (i = 0; i <=n; i++)
    {
        a[i] = (i+1)*2;

        if (i%2==0) b[i] = 2*i;
            else b[i] = -2*i;

        c[i] = a[i] - b[i];

    }
    cout << "A" << setw(3) << "B" << setw(3) << "C" << endl;
    cout << a[i] << setw(3) << b[i] << setw(3) << c[i] << endl;
}

And it shows me "Process returned -1073741571 (0xC00000FD)" Can't find what is problem. When I try other code, it works. Platform is Win 10.

c++
asked on Stack Overflow Dec 8, 2020 by Djordje Rankovic

3 Answers

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You are using a non-standard variable-length array (VLA) C++ extension, and you have stack overflow because n is not initialized before declaring arrays like a[n].

If you want to keep using VLA, need to move declaration int a[n], b[n], c[n]; below cin >> n;. Or use std::vector<int> instead.

answered on Stack Overflow Dec 8, 2020 by Eugene
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This line:

int i, n, a[n], b[n], c[n];

has two problems:

  1. Variable length arrays are non-standard, and:

  2. n is uninitialised so a[n] tries to allocate an array of some indeterminate size on the stack. Which, in your case, is too large and is causing a stack overflow.

So, initialise n before you use it, and rather than using variable length arrays, use std::vector.

answered on Stack Overflow Dec 8, 2020 by Paul Sanders
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Achieved to find solution... Here is the final result:

#include <iostream>
#include <iomanip>
using namespace std;
main()
{
    int i, n, a[100], b[100], c[100];

    cout << "Program kreira nizove po matematickoj zavisnosti" << endl;
    cout << "Unesite vrednost n = ";
    cin >> n;
    cout << "A" << setw(10) << "B" << setw(10) << "C" << endl;

    for (i = 0; i <= n; i++)
    {
        a[i] = (i+1)*2;

        if (i%2==0) b[i] = 2*i;
            else b[i] = -2*i;

        c[i] = a[i] - b[i];

        cout << a[i] << setw(10) << b[i] << setw(10) << c[i] << endl;
    }
}

I changed value of array to something I'll never use (like 100) and I put cout in for loop, so it can type results one under other. It managed to work perfectly. Thank you for your help!

answered on Stack Overflow Dec 8, 2020 by Djordje Rankovic

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