is getting msb and lsb using the same mask portable with respect to endianess?

Assuming the following C code runs on a 32 bit platform (so sizeof(int) = 4), is the following code portable between big endian and little endian? When I ask "is it portable" I mean is the app going to print:

a) on a little endian platform

Address is 0xAABBCCDD
MSB is AA
LSB is DD
little endian

b) on a big endian platform

Address is 0xAABBCCDD
MSB is AA
LSB is DD
big endian

?

#include <stdio.h>

typedef unsigned char uint8;
typedef unsigned int uint32;

#define is_bigendian() ( (*(uint8*)&var) == 0 )

int main()
{
    uint32 var = 1;
    uint8 msb;
    uint8 lsb;
    printf("Address is %x\n", (uint32)&var);
    msb = (((uint32)&var) & 0xFF000000) >> 24;
    lsb = (((uint32)&var) & 0x000000FF) >> 0;
    printf("MSB is %x\n", msb);
    printf("LSB is %x\n", lsb);
    if (is_bigendian())
    {
        printf("big endian\n");
    }
    else
    {
        printf("little endian\n");
    }
    return 0;
}