Error code = 0x80070002 (MS Visual Studio) C++ for searching triplet data from one key element

-1

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How finding a map triplet pair with one element for example (4,(?,?)) so i know that int 4 -> how can i find it because i get so much error and four hours of searching for possible solution to filter the coordinates with that key.

 int k = *min_element(min1.begin(), min1.end());

 auto it = myninja.begin(); 
 it = find(myninja.begin(), myninja.end(), k);
 for (it = myninja.begin(); it != myninja.end(); it++) {
     p.row= (it->second).first;
     p.col = (it->second).second;
 }

these are my declarations

vector <pair<int, pair<int, int> > > myninja; 
    vector <int> min1; 

and this is where i want to put out my min for A* -> f value for minimum range to goal

 int k = *min_element(min1.begin(), min1.end());

to keep the actual value from this i want to update the start point with the minimum of f -> so i want to give the point (x,y) so i thought

vector <pair<int, pair<int, int> > > myninja;

would be the best, but always i want to find out from which f(n) value it comes from -> error in iterator/loop or it displays me errorcode

i think i comes from the find function because maybe he can't handle a int k (which i want to search my points)

(F-Value,(x-coordinate,y-coordinate)

also this is not working

int k = *min_element(min1.begin(), min1.end());
auto result = std::find_if(myninja.begin(),myninja.end(),[k](const auto& mo){return mo.second == val; });

 //RETURN VARIABLE IF FOUND
  if (result != myninja.end())
  int foundkey = (result->second).first;
c++
algorithm
visual-c++
path-finding
asked on Stack Overflow May 30, 2020 by SuperAfsd • edited May 30, 2020 by SuperAfsd

1 Answer

0
int s = myninja.size();
int j = min1.size(); 

for (int i = 0; i < s; i++)
{
min1.push_back(myninja[i].first);
}

int mic = min1[0];

for (int i = 0; i <j; i++)
 {
 if (min1[i] < mic)
 mic = min1[i];
 }

 cout << mic;

for (int i = 0; i < s; i++)
{
if (myninja[i].first == mic) {

// "first" and "second" are used to access 
// 1st and 2nd element of pair respectively 

p.row = myninja[i].second.first;
p.col = myninja[i].second.second;

q.push(objects(p.row, p.col, p.dist+1));

cout << "Min Punkt";
cout << " x " << p.row << " y " << p.col;

cout << "Distanz"; 
cout << p.dist;

visit[p.row][p.col] = true;
break;

}
}

// Finally it works but it saves now the same point again and again with the minimum of f.
// i am working on to delete or set it true so after the calculation -> get the new point with other f minimum till the goal.
answered on Stack Overflow May 30, 2020 by SuperAfsd

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