How finding a map triplet pair with one element for example (4,(?,?)) so i know that int 4 -> how can i find it because i get so much error and four hours of searching for possible solution to filter the coordinates with that key.

```
int k = *min_element(min1.begin(), min1.end());
auto it = myninja.begin();
it = find(myninja.begin(), myninja.end(), k);
for (it = myninja.begin(); it != myninja.end(); it++) {
p.row= (it->second).first;
p.col = (it->second).second;
}
```

these are my declarations

```
vector <pair<int, pair<int, int> > > myninja;
vector <int> min1;
```

and this is where i want to put out my min for A* -> f value for minimum range to goal

```
int k = *min_element(min1.begin(), min1.end());
```

to keep the actual value from this i want to update the start point with the minimum of f -> so i want to give the point (x,y) so i thought

```
vector <pair<int, pair<int, int> > > myninja;
```

would be the best, but always i want to find out from which f(n) value it comes from -> error in iterator/loop or it displays me errorcode

i think i comes from the find function because maybe he can't handle a int k (which i want to search my points)

(F-Value,(x-coordinate,y-coordinate)

also this is not working

```
int k = *min_element(min1.begin(), min1.end());
auto result = std::find_if(myninja.begin(),myninja.end(),[k](const auto& mo){return mo.second == val; });
//RETURN VARIABLE IF FOUND
if (result != myninja.end())
int foundkey = (result->second).first;
```

```
int s = myninja.size();
int j = min1.size();
for (int i = 0; i < s; i++)
{
min1.push_back(myninja[i].first);
}
int mic = min1[0];
for (int i = 0; i <j; i++)
{
if (min1[i] < mic)
mic = min1[i];
}
cout << mic;
for (int i = 0; i < s; i++)
{
if (myninja[i].first == mic) {
// "first" and "second" are used to access
// 1st and 2nd element of pair respectively
p.row = myninja[i].second.first;
p.col = myninja[i].second.second;
q.push(objects(p.row, p.col, p.dist+1));
cout << "Min Punkt";
cout << " x " << p.row << " y " << p.col;
cout << "Distanz";
cout << p.dist;
visit[p.row][p.col] = true;
break;
```

}

}

```
// Finally it works but it saves now the same point again and again with the minimum of f.
// i am working on to delete or set it true so after the calculation -> get the new point with other f minimum till the goal.
```

answered on Stack Overflow May 30, 2020 by SuperAfsd

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