I new to Solaris, am trying to get shared memory usage in Solaris 11.
I logged-in as root and tried below commands.
ipcs -am IPC status from <running system> as of Tue Oct 1 12:14:30 IST 2019 T ID KEY MODE OWNER GROUP CREATOR CGROUP NATTCH SEGSZ CPID LPID ATIME DTIME CTIME Shared Memory: m 3 0xffffffff --rw-rw-rw- root root root root 0 1024 9798 10993 15:14:41 15:14:46 15:13:43
It gave me 1024 bytes for shared memory id 3
id -p uid=0(root) gid=0(root) projid=1(user.root) prctl -n project.max-shm-memory -i project user.root project: 1: user.root NAME PRIVILEGE VALUE FLAG ACTION RECIPIENT project.max-shm-memory usage 8.00KB privileged 623GB - deny - system 16.0EB max deny
Here I got 8 KB as usage.
In oracle documents it is written as
The prctl utility allows the examination and modification of the resource controls (rctl) associated with an active process, task, project or zone on the system. It allows access to the basic and privileged limits and the current usage on the specified entity.
Here i am confused which is current usage of shared memory ? 1024 bytes or 8 KB?
Memory is allocated on most operating systems in pages. 8 kb is the default, smallest page size on Solaris SPARC systems, thus the 1 kb shared memory segment actually uses one 8 kb page of memory.
The available page sizes for a Solaris system can be listed using the
pagesize -a command:
pagesizeutility prints the default size of a page of memory in bytes, as returned by
getpagesize(3C). This program is useful in constructing portable shell scripts. Options
The following option is supported:
-a Prints out all possible hardware address translation sizes supported by the system.
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