How to handle System.Runtime.InteropServices.COMException (0x800706BA): The RPC server is unavailable. (Exception from HRESULT: 0x800706BA)

1

I am developing a Windows application where I manipulate Word Application. More specific, I am opening a Word Document but when I quit it and try to open another Word Document this Error comes out.

How to handle

System.Runtime.InteropServices.COMException (0x800706BA): The RPC server is unavailable. (Exception from HRESULT: 0x800706BA) at Microsoft.Office,Word.ApplicationClass.set_Visible(Boolean Prop)**

If I don't quit the Word Application this error does not come out.

Below I show you the functions that I open and quit the Word Application.

    //function to open word Document located in a specific path
        public static void openWordDocument(string fileName)
        {
            try
            {
                wordApplication.Visible = true;
                string filePath = myPath + fileName;
                WordApi.Document docx = wordApplication.Documents.Open(filePath);
            }
            catch (Exception ex)
            {
                MyLogger.Error(ex.ToString());
            }
        }



//function to quit wordApplication 
  public static void CloseWordApp() {

            try {
                Object wordAppObject = Marshal.GetActiveObject("Word.Application");
                WordApi.Application wordApp = (WordApi.Application)wordAppObject;  //cast Object to its actual type
                wordApp.Quit();
            }
            catch (Exception ex) {
                 MyLogger.Error(ex.ToString());
            }


c#
winforms
office-interop
comexception
asked on Stack Overflow Jun 27, 2019 by Tsal Giorgos • edited Jun 27, 2019 by MickyD

2 Answers

1

Most probably the exception is fired by the following line of code:

wordApplication.Visible = true;

You need to make sure the COM server is alive. Because after quitting the object becomes unavailable. I'd suggest setting such object references to null, so later we could check whether the application object is still alive. For example:

try
{
    if (wordApplication == null)
    {
        wordApplication = new Word.Application();
    }
    wordApplication.Visible = true;
    string filePath = myPath + fileName;
    WordApi.Document docx = wordApplication.Documents.Open(filePath);
}
catch (Exception ex)
{
    MyLogger.Error(ex.ToString());
}
answered on Stack Overflow Jun 27, 2019 by Eugene Astafiev • edited Jun 27, 2019 by JohnyL
1

I finally figured it out what is the problem. The main problem was that when I quit it and try to open another Word Document,which opening another Word Document means get/create an Object of Word Application. In my case wordApp != null, after finalizing the application, so I had to create another Word Application Object and return it for the case.

  //open word Document located in a specific path
    public static void openWordDocument(string fileName)
    {
        try
        {
            wordApplication = createWordApplicationObject(wordApplication);
            wordApplication.Visible = true;
            string filePath = myPath + fileName;
            WordApi.Document docx = wordApplication.Documents.Open(filePath);
        }
        catch (Exception ex)
        {
            MyLogger.Error(ex.ToString());
        }
    }
private static WordApi.Application createWordApplicationObject(WordApi.Application wordApp)
    {
        WordApi.Application wordAppFirstTime;
        WordApi.Application wordApp1;
        if (wordApp == null)
        {
            wordAppFirstTime = new WordApi.Application();
            return wordAppFirstTime;

        }
        else
        {
            wordApp1 = new WordApi.Application();
            return wordApp1;
        }

    }

With CloseWordApp() remain the same.

answered on Stack Overflow Aug 3, 2019 by Tsal Giorgos

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