I'm trying to compile some C code to run on an ARMv6 simulator, with FLASH memory starting @ 0x0 and RAM starting at 0x800000. Right now, I can pass binary files off the the simulator just fine...
However, I want the instructions generated to not include any writes to flash memory, and only operate within RAM memory (after copying RAM). Is this possible?
I am using the GNU toolchain to compile.
This is my current linker script:
MEMORY
{
rom(rx) : ORIGIN = 0x00000000, LENGTH = 0x00800000
ram(!rx) : ORIGIN = 0x40000000, LENGTH = 0x00800000
h : ORIGIN = 0x40000000, LENGTH = 0x00400000
}
SECTIONS
{
.text : { *(.text*) } > rom
.bss : { *(.bss*) } > ram
.heap : { *(.heap*) } > h
}
end = ORIGIN(h) + LENGTH(h);
_stacktop = ORIGIN(ram) + LENGTH(ram);
Your build linker script (normally a .ld file) determines the locations of your device's memory and how the linker sections are mapped to that. Your link map should not include writable sections in read-only memory, that will fail.
[Added after linker script added to question]
You linker script seems unusual in lacking a .data section:
.data : { *(.data) } > ram
Without that it is not clear what the linker will do with static initialised data.
Also your question states that the RAM starts at 0x800000, but the linker script clearly locates it at 0x40000000. Perhaps this misunderstanding of your memory map is leading you to erroneously believe that writes to the ROM region are occurring?
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