How to fix passing argument 1 of 'count' from incompatible pointer type

I am trying to make a C language program with a linked list that uses recursion to count the total of the linked list nodes. However, I get this error:

passing argument 1 of 'count' from incompatible pointer type [-Wincompatible-pointer-types]|

Can anyone explain to me why this happen and how to fix it?

This is linked list node without recursion. It works without error and gives return the value that I need.

int count(list_t *list){
    node_t *curr = list->head;
    int length=0;
    while(curr != NULL){
        length++;
        curr = curr->next;
    }
    return(length);
}

And this one is recursive, but I get the "'count' from incompatible pointer" error.

int count(list_t *list){
    node_t *curr = list->currptr;
    int length=0;
    if(curr == NULL){
        return(0);
    }
    return(1 + count(curr->next));
}

This is structure of my linked list

typedef struct {
    int yyyy, mm,dd;
} date_t;

typedef struct {
    double balance;
} acc_balance;

typedef struct node node_t;

struct node{
    char *acc_no, *name, *lastname;
    date_t date;
    acc_balance acc_balance;
    node_t *next;
};

typedef struct {
    node_t *head;
    node_t *foot;
    node_t *currptr;
} list_t;

The output should be 8 but the program is terminated with:

Process returned -1073741819 (0xC0000005) execution time : 5.093 s

I'm still new to StackOverflow. My apologies if I said something wrong.

Thank you for posting the definitions. That is very helpful. For recursion, you only need to deal with the node_t and not the list_t. It might look like this:

int count(node_t *curr)
{
    if (curr == NULL)
    {
        return (0);
    }
    return (1 + count(curr->next));
}

Then you call it like this:

count(list->head);

If you want to be able to call it with a list_t, then add a helper function like this:

int countList(list_t *list)
{
    return count(list->head);
}