Address operator and variable token joining macro

0

I have had a problem with running a program that (when simplified) looks something like this.

#include <stdio.h>
#define ADDR_TOKEN_MACRO(x) & ## x
int main() {
    int *i;
    int **y;
    int b = 0xDEADBEEF;
    *y = ADDR_TOKEN_MACRO(b);
    return 0;
}

I'm trying to set the integer pointer i's address to 0xDEADBEEF, but if I wanted to have the address be inputted by the user, I have come to the conclusion that this is the best way to do so. However, I keep getting this error:

error: pasting "&" and "b" does not give a valid preprocessing token

First of all, is the idea behind the program even possible in C? And if the first question is true, can a macro like this be implemented?

c
asked on Stack Overflow Dec 1, 2018 by brokenc0de

1 Answer

2

Your macro is trying to take & and b and combine it into a single token &b. This is not a valid identifier, so you can't do this. What you want however is simpler than that:

#define ADDR_TOKEN_MACRO(x) &x

Now you have the address-of operator applied to the given token.

Actually, using a macro doesn't make much sense here at all. You can just do this:

*y = &b;

This is a problem however because y was not assigned a value but you try to dereference y. I think what you're really trying to do is:

int *i = (int *)0xDEADBEEF;

But then it's also questionable if you really want to do this, because the user shouldn't need to know anything about a specific address.

answered on Stack Overflow Dec 1, 2018 by dbush

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