C# Cant find object reference when using terminal.gui

0

Ive been playing around with some server/client stuff and though id try using terminal.gui, and for some reason that i dont understand its acting up. i have 2 scripts; one to handle the backend stuff and one to handle the user interface/interraction.

script1:

using UI;

namespace ServerTest
{
    public class Server
    {
        static void Main() 
        {
            UI.UI.main();
            StartServ();
            RecieveConn.Start();
            MngSockets.Start();
        }
    }
}

script 2:

using ServerTest;
using Terminal.Gui;

namespace UI
{
    public class UI
    {
        static Window win = new Window(new Rect(0, 0, Application.Top.Frame.Width, Application.Top.Frame.Height), "MyApp");
        public static void main()
        {
            Application.Init();
            win.Add(new Label(0, 0, "asd"));

            Application.Run(win);
        }
    }
}

This gives me the error:

System.TypeInitializationException
  HResult=0x80131534
  Message=The type initializer for 'UI.UI' threw an exception.
  Source=Server
  StackTrace:
   at UI.UI.main() in C:\Users\ThisPc\Desktop\ConsoleApp2\ConsoleApp2\ui.cs:line 29
   at ServerTest.Server.Main() in C:\Users\ThisPc\Desktop\ConsoleApp2\ConsoleApp2\Program.cs:line 23

Inner Exception 1:
NullReferenceException: Object reference not set to an instance of an object.

Though, if i do this it works:

using ServerTest;
using Terminal.Gui;

namespace UI
{
    public class UI
    {
        public static void main()
        {
            Window win = new Window(new Rect(0, 0, Application.Top.Frame.Width, Application.Top.Frame.Height), "MyApp");

            Application.Init();
            win.Add(new Label(0, 0, "asd"));

            Application.Run(win);
        }
    }
}

but then i cant use the win variable in other functions... Thanks in advance =)

c#
.net
visual-studio
user-interface
asked on Stack Overflow Nov 11, 2018 by Asperix

1 Answer

0

Thx mjwills for the answer...

just do

using ServerTest;
using Terminal.Gui;

namespace UI
{
    public class UI
    {
        static Window win = null;
        public static void main()
        {
            win = new Window(new Rect(0, 0, Application.Top.Frame.Width, Application.Top.Frame.Height), "MyApp");

            Application.Init();
            win.Add(new Label(0, 0, "asd"));

            Application.Run(win);
        }
    }
}
answered on Stack Overflow Nov 11, 2018 by Asperix

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