Assembly basics - multiple arguments

0

Suppose I have the following snippet:

push  ebp                       (1)
mov   ebp,esp                   (2)
mov   eax,0xaf                  (3)
xor   al,al                     (4)
mov   ah,BYTE PTR [ebp+0x9]     (5)

And I call this with the following arguments: 0xdeadbeef, 0xdeefbeab, 0xf00b1den. I'm basically unsure of BYTE PTR is. My assumption:

at (3) the eax stack looks as follows (grouped in 8 for readability):

00000000 00000000 00000000 10101111

at (4):

00000000 00000000 00000000 00000000

at (5):

Is then 0xb1 (the 9th byte in my argument taken as an array) moved in?

00000000 00000000 10110001 00000000

assembly
x86
asked on Stack Overflow Oct 1, 2018 by S. L. • edited Oct 1, 2018 by S. L.

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