I am writing a command line application in VB.NET. This application is calling another one, msxsl.exe, to run an XSL transform. I am using the Process class to do this:
Dim process = New Process()
process.StartInfo.FileName = "msxsl.exe"
process.StartInfo.Arguments = "base.xml test.xsl -o styled.xml"
process.StartInfo.UseShellExecute = False
process.StartInfo.CreateNoWindow = True
process.StartInfo.RedirectStandardOutput = True
process.Start()
This part works great. What I want it to be able to display the output from this process to the console of my application. I have read several posts explaining this method, but it does not seem to work in this case. The output is an empty string.
Dim output As String = process.StandardOutput.ReadToEnd()
process.WaitForExit()
Console.WriteLine(output)
I have verified that if I run the msxsl executable on its own (i.e. running "msxsl.exe base.xml test.xsl -o styled.xml"), it displays output on the command line. What am I doing wrong?
EDIT: I should note that the msxsl process is currently failing due to a malformed XML file. It is displaying this error message:
Error occurred while executing stylesheet 'test.xsl'.
Code: 0x800c0006
The system cannot locate the object specified.
This is exactly the type of thing I want displayed in the console of my application (or, eventually, a log file.)
This is probably because this isn't standard output it is StandardError
you will want to redirect StandardError
like so Process.StartInfo.RedirectStandardError = True
and then read that into a string.
Dim ErrorString As String = Process.StandardError.ReadToEnd()
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