What does ulConfig |= ulMode; mean?

0

I am not really sure what does ulConfig |= ulMode; mean? If

void gpio_setup_mode(unsigned long ulGpioNum, unsigned long ulMode, unsigned long ulInvert)
{
  unsigned long ulConfig = ulInvert;
  ulConfig |= ulMode;
  s_ptGPIO->auiCFG[ulGpioNum] = ulConfig;
}

and

 gpio_setup_mode(GPIO8,  GPIO_MODE_OUTPUT,     GPIO_NOINVERT); 

where GPIO8, GPIO_MODE_OUTPUT, GPIO_NOINVERT

#define GPIO8                         8    
#define GPIO_NOINVERT         0x00000000 
#define GPIO_MODE_OUTPUT     0x00000011 
c
microcontroller
asked on Stack Overflow Jul 19, 2015 by user3826752

1 Answer

2
ulConfig |= ulMode;

is equivalent to

ulConfig = ulConfig | ulMode;

The |-operator performs a binary "or" operation between the two operants.

From the C11-Standard (Draft):

6.5.12 Bitwise inclusive OR operator

[...]

Contrains

2 Each of the operands shall have integer type.

Semantics

[...]

4 The result of the | operator is the bitwise inclusive OR of the operands (that is, each bit in the result is set if and only if at least one of the corresponding bits in the converted operands is set).

answered on Stack Overflow Jul 19, 2015 by alk • edited Jul 19, 2015 by alk

User contributions licensed under CC BY-SA 3.0