I saw in MSDN documents that the maximum value of
I think, if it's
Int32 it should store 32-bit integer values that finally should be
4,294,967,295 and hexadecimal
My question is why
Int32 stores 31-bit integer values?
It's because it's a signed integer. An unsigned 32-bit integer give you the value you expect.
Check out this MSDN page - http://msdn.microsoft.com/en-us/library/exx3b86w(v=vs.80).aspx
For a more in depth explanation on why this is check out the link in Jackson Popes answer related to Two's Complement number representation.
Also some further reading.
Int32 and Int64 are both signed so they can handle integer values from -capacity/2 to (capacity/2)-1 (for zero) that is why the max value isn't the one you expected. But you can get what you want by using an unsigned int to have only positive numbers.
You are not considering the negative numbers.
Int32 have the sign.
From MSDN: http://msdn.microsoft.com/en-us/library/system.int32.minvalue.aspx
-2,147,483,648; that is, hexadecimal
In a 2's complement signed n-bit type, the range is from -2n-1 to 2n-1-1 because with n bits you can represent 2n different values, half of which is used for signed numbers because of the sign bit. The remaining 2n-1 half is used for non-negative number. Since one is used for 0, there are only 2n-1-1 remaining values for positive numbers
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